The distance between the points (a cos35∘,0) & (0,a cos55∘) is
a
2a
3a
4a
cos 35 = sin 65 Applying distance formula we get
⇒√(a cos35∘−0)2+(0−a cos55∘)2
⇒√a2cos235∘+a2cos255∘
⇒√a2(cos235∘+cos255∘)
Since cos 55 = sin 35 and sin2x + cos2x = 1 ⇒√a2=a