The distance between the polars of the foci of the Ellipse x2-25-y2-9-1 w-r-to itself is

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Thermal Expansion

The distance ...

Question

The distance between the polars of the foci of the Ellipse $\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1$ w.r.to itself is

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\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1

P (x_{1}, y_{1})

\frac{x^{2}}{9} + \frac{y^{2}}{25} = 1

\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1

2

P (x_{1}, 5)

\frac{x^{2}}{9} + \frac{y^{2}}{25} = 1

P

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\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1

\frac{π}{8}

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