The distance between the straight lines $y = m x + c_{1}, y = m x + c_{2}$ is $| c_{1} - c_{2} |$ , then $m =$

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Solution

The correct option is A $0$
$d = ∣ ∣ ∣ \frac{c_{1} - c_{2}}{\sqrt{1 + m^{2}}} ∣ ∣ ∣$ ...(1)
Given $d = | c_{1} - c_{2} |$ ...(2)
From (1) & (2),
$\sqrt{1 + m^{2}} = 1$
$\Rightarrow m = 0$

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Similar questions

Q. The distance between two straight lines

y = m x + c_{1}

and

y = m x + c_{2}

| c_{1} - c_{2} |

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(a)

\frac{c_{1} - c_{2}}{\sqrt{1 + m^{2}}}

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(d)

|c_{1} - c_{2}|

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The distance between the straight lines y=mx+c1, y=mx+c2 is |c1−c2|, then m=

The correct option is A 0d=∣∣∣c1−c2√1+m2∣∣∣ ...(1)Given d=|c1−c2| ...(2)From (1) & (2),√1+m2=1⇒m=0

The distance between the straight lines $y = m x + c_{1}, y = m x + c_{2}$ is $| c_{1} - c_{2} |$ , then $m =$

The correct option is A $0$
$d = ∣ ∣ ∣ \frac{c_{1} - c_{2}}{\sqrt{1 + m^{2}}} ∣ ∣ ∣$ ...(1)
Given $d = | c_{1} - c_{2} |$ ...(2)
From (1) & (2),
$\sqrt{1 + m^{2}} = 1$
$\Rightarrow m = 0$