The distance between the tops of two trees 20 m and 28 m high is 17 m. The horizontal distance between the trees is
15 m
Let AB and CD be two trees such that AB = 20 m, CD = 28 m & BD = 17 m
Draw BE perpendicular to CD. Then, ED = 8 m.
∴ BE = √BD2−ED2 = √(17)2−82
= √225 = 15m.
∴ AC = BE = 15m.