The distance between two buildings is 24m. The heights of the buildings are 12m and 22m. Find the distance between the tops (in m).
A
20
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B
26
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C
30
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D
32
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Solution
The correct option is B26 From the diagram, PB=CD=12m AP=AB−PB=(22−12)m=10m Also CP=BD=24 m Since △APC is a right angled triangle, AC2=AP2+PC2 AC2=102+242 AC2=676 ∴AC=26 m Hence, distance between their tops is 26m.