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Standard XII

Physics

TIR in Prism

The distance ...

Question

The distance between two coherent sources produced by a bi-prism is $1.0 m m$ . When distance between the source and the screen is $0.9 m$ , the fringe width obtained is $0.12 m m$ . If the screen is placed at a distance of $1.8 m$ , then the fringe width will be

0.6 m m

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0.8 m m

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0.9 m m

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0.24 m m

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Solution

The correct option is D $0.24 m m$
Fringe width for a bi-prism is given by $ω = \frac{D λ}{d}$
$ω \propto D$
$D$ doubles, hence $ω$ doubles.

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The distance between two coherent sources produced by a bi-prism is 1.0mm. When distance between the source and the screen is 0.9m, the fringe width obtained is 0.12mm. If the screen is placed at a distance of 1.8m, then the fringe width will be

The correct option is D 0.24mmFringe width for a bi-prism is given by ω=Dλdω∝DD doubles, hence ω doubles.

The distance between two coherent sources produced by a bi-prism is $1.0 m m$ . When distance between the source and the screen is $0.9 m$ , the fringe width obtained is $0.12 m m$ . If the screen is placed at a distance of $1.8 m$ , then the fringe width will be

The correct option is D $0.24 m m$
Fringe width for a bi-prism is given by $ω = \frac{D λ}{d}$
$ω \propto D$
$D$ doubles, hence $ω$ doubles.