The distance between two consecutive crests in a wave train produced in a string is $5 c m$ . If two complete waves pass through any point per second. The velocity of the wave is

15 c m s^{- 1}

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10 c m s^{- 1}

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2.5 c m s^{- 1}

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5 c m s^{- 1}

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Solution

The correct option is A $10 c m s^{- 1}$
Wavelength $λ =$ distance between two consecutive crests $= 5 c m .$
Frequency $ν = 2$ . Hence $v = ν \times λ = 10 c m / s$

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The distance between two consecutive crests in a wave train produced in a string is 5 cm. If two complete waves pass through any point per second. The velocity of the wave is

The correct option is A 10 cms−1Wavelength λ= distance between two consecutive crests =5cm.Frequency ν=2. Hence v=ν×λ=10cm/s

The distance between two consecutive crests in a wave train produced in a string is $5 c m$ . If two complete waves pass through any point per second. The velocity of the wave is

The correct option is A $10 c m s^{- 1}$
Wavelength $λ =$ distance between two consecutive crests $= 5 c m .$
Frequency $ν = 2$ . Hence $v = ν \times λ = 10 c m / s$