The distance between two consecutive crests in a wave train produced in a string is 5cm. If two complete waves pass through any point per second. The velocity of the wave is
A
15cms−1
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B
10cms−1
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C
2.5cms−1
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D
5cms−1
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Solution
The correct option is A10cms−1 Wavelength λ= distance between two consecutive crests =5cm. Frequency ν=2. Hence v=ν×λ=10cm/s