The distance between two consecutive crests in a wave train produced on a string is $5 c m$ . If two complete waves pass through any point per second, the velocity of the wave is

10 c m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.5 c m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 c m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 c m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $10 c m s^{- 1}$
The distance between two consecutive crests in a wave is nothing but wavelength $λ .$ Two complete waves pass through any point per second means the frequency(f) is 2Hz.
Velocity $v = f λ = 5 \times 2 = 10 c m / s$

Suggest Corrections

Similar questions

The distance between two consecutive crests in a wave train produced in a

string is 5 cm. If 2 complete waves pass through any point per second, the

velocity of the wave is [CPMT 1990]

The distance between two consecutive crests in a wave train produced in a string is 5 cm. If 2 complete waves pass through any point per second, the velocity of the wave is

Q. The distance between two consecutive crests in a wave train produced in string is

5 m

. If two complete waves pass through any point per second, the velocity of wave is :

Q. If the distance between two consecutive crests is

5

cm and

2

waves passes from a point in one second the wave velocity is-

The separation between two consecutive crests in a transverse wave is 100 m. If wave velocity is 20 m $s^{- 1}$ , find the frequency of wave.

Join BYJU'S Learning Program

The distance between two consecutive crests in a wave train produced on a string is 5cm. If two complete waves pass through any point per second, the velocity of the wave is

The correct option is C 10cms−1The distance between two consecutive crests in a wave is nothing but wavelengthλ. Two complete waves pass through any point per second means the frequency(f) is 2Hz.Velocity v=fλ=5×2=10cm/s

The distance between two consecutive crests in a wave train produced on a string is $5 c m$ . If two complete waves pass through any point per second, the velocity of the wave is

The correct option is C $10 c m s^{- 1}$
The distance between two consecutive crests in a wave is nothing but wavelength $λ .$ Two complete waves pass through any point per second means the frequency(f) is 2Hz.
Velocity $v = f λ = 5 \times 2 = 10 c m / s$