The distance between two neutral atoms in equilibrium is :

\sqrt{\frac{2 A}{B}}

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{(\frac{2 A}{B})}^{\frac{1}{6}}

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\frac{2 A}{B}

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{(\frac{2 A}{B})}^{\frac{1}{2}}

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Solution

The correct option is A ${(\frac{2 A}{B})}^{\frac{1}{6}}$
The distance between two neutral atoms in equilibrium is ${(\frac{2 A}{B})}^{\frac{1}{6}}$ .
This is obtained when the value of the force F is substituted as zero in the expression for the force which is $F = \frac{12 A}{r^{13}} - \frac{6 B}{r^{7}}$ .

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The distance between two neutral atoms in equilibrium is :

The correct option is A (2AB)16The distance between two neutral atoms in equilibrium is (2AB)16.This is obtained when the value of the force F is substituted as zero in the expression for the force which is F=12Ar13−6Br7.