Question

The distance between two particles is decreasing at the rate of $6\frac{m}{sec}$. If these particles travel with same speeds as in previous case and in the same direction, then the separation increase at the rate of $4\frac{m}{sec}$. The particles have speeds as

• A. $5\frac{m}{sec};1\frac{m}{sec}$
• B. $4\frac{m}{sec};1\frac{m}{sec}$
• C. $4\frac{m}{sec};2\frac{m}{sec}$
• D. $5\frac{m}{sec};2\frac{m}{sec}$

Answer 1

The correct option is A $5\frac{m}{sec};1\frac{m}{sec}$

When two particles moves towards each other then $v_1+v_2=6.....\left(i\right)$
When these particles moves in the same direction then $v_1-v_2=4.....\left(ii\right)$
By solving $v_1=5$ and $v_2=1\frac{m}{s}$