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Question

The distance between two places is 900km. An ordinary express train takes 5hours more than a superfast train to cover this distance. If the speed of the superfast express train is 15km/hr more than that of the ordinary express train, find the speeds of the train.


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Solution

Step 1: Given data

Let the speed of the ordinary train be xkm/hr.

Distance between two places is 900km.

Time taken to cover the distance by ordinary train will be t=distancespeed.

t=900x

Speed of the superfast express train is 15km/hr more than that of the ordinary express train.

Time taken to cover the same distance by superfast express train will be,

T=900x+15

Step 2: Determining the quadratic equation

According to the question,

An ordinary express train takes 5hours more than a superfast train to cover the same distance.

t-T=5900x-900x+15=5900x+15-900xxx+15=5900x+13500-900xxx+15=5

After simplification,

13500=5xx+155x2+75x-13500=05x2+15x-2700=0x2+15x-2700=0

Step 3: Determining the speeds of the train

To solve the obtained equation by split the middle term method, we choose two numbers such as their sum is equal to b and product is equal to a×c.

x2+60-45x-2700=0x2+60x-45x-2700=0xx+60-45x+60=0x+60x-45=0

After simplification,

x=-60,45

Here, x=-60 is not considerable as speed cannot be negative.

Therefore, speed of an ordinary express train is 45km/hr.

Speed of superfast express train is 15km/hr more than that of the ordinary express train.

Therefore, speed of an superfast express train is 60km/hr.


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