Question

The distance between two points differing in phase by ${60}^{\circ }$ on a wave having a wave velocity $360m/s$ and frequency $500Hz$ is

• A. $0.72m$
• B. $0.18m$
• C. $0.12m$
• D. $0.36m$

Answer 1

The correct option is C $0.12m$

Given : $\delta ={60}^o=\frac{\pi }{3}$, $v=360m/s$ $\nu =500Hz$

So, wavelength of wave $\lambda =\frac{v}{\nu }=\frac{360}{500}=0.72m$

Distance between two points $\Delta x=\frac{\lambda }{2\pi }\times \delta$

$\therefore$ $\Delta x=\frac{0.72}{2\pi }\times \frac{\pi }{3}=0.12m$