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Question

The distance between two stations is 300 km. Two motorcyclists start simultaneously from these stations and move towards each other. The speed of one of them is 7 km/h more than that of the other. If the distance between them after 2 hours of their start is 34 km, find the speed of each motorcyclist. Check your solution.

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Solution

Let the speed of one motorcyclist be x km/h.So, the speed of the other motorcyclist will be ( x+7 ) km/h.Distance travelled by the first motorcyclist in 2 hours = 2x kmDistance travelled by the second motorcyclist in 2 hours = 2 ( x+7 ) kmTherefore,300 - ( 2x + (2x +14) ) = 34 300 - ( 2x + 2x + 14 ) = 34 300 -4x - 14 = 34 286 - 4x = 34 286 - 34 = 4x 252 = 4x x= 2524 = 63Therefore, the speed of the first motorcyclist is 63 km/h.The speed of the second motorcyclist is ( x+7 ) = ( 63+7 ) = 70 km/h.Check:The distance covered by the first motorcyclist in 2 hours = 63 ×2 = 126 kmThe distance covered by the second motorcyclist in 2 hours = 70 ×2 = 140 kmThe distance between the motorcyclists after 2 hours = 300 - ( 126 + 140 ) = 34 km (which is the same as given)Therefore, the speeds of the motorcyclists are 63 km/h and 70 km/h, respectively.

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