The distance between two stations is 425 km. Two trains start simultancously from these
station on parallel tracks to cross each other. The speed of one of them is greater than that of the other by 5 km/hr. If the distance between the two trains after 3 hours of their start is 20 km
, find the speed of each train.

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Solution

Let the trains be A and B.
Speed of A = x km/h
Speed of B = (x+5) km/h

After 3 hours,
distance travelled by A = 3x km
distance travelled by B = 3(x+5) km = 3x+15 km

now distance between them is 20km
So 3x + (3x+15) + 20 = 425
6x + 35 = 425
6x = 425 – 35 = 390
x = 390/6 = 65 km/h
x + 5 = 65+5 = 70 km/h

Speed of the trains are 65 km/h and 70 km/h.

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