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Question

The distance covered by a particle thrown in a vertical plane in horizontal and vertical directions at any instance of time t are x=21t m and y=(2t4t2) m respectively. The initial velocity of the particle (in m/s) is

A
5
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B
10
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C
15
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D
20
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Solution

The correct option is A 5
Second equation of motion in horizontal and vertical direction of motion,
x - direction:x=ux t
y - direction:y=uyt12gt2
Compare the above equations from the equations given in questions, we get ux=21;uy=2
Hence initial velocity of particle is the resultant of these two components of velocity
u=u2x+u2y
=21+4
=5 ms1

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