Question

The distance covered by the second body when they meet is

• A. 8 m
• B. 16 m
• C. 24 m
• D. 32 m

Answer 1

The correct option is D 32 m

$A\to 8m/s$

$B\to 4m/s^2$

Let us observe the motion of A wrt B.

So,

$a_{A/B}=-4m/s^2$

$u_{A/B}=8m/s$

For finding the time after they

will meet

Applying $2^{nd}$ $e{n}^n$ of motion

$0=\left(u_{A/B}\right)t$ $t\frac{a_{A/B}}{2}{t}^2$

$\Rightarrow 0=8t-\frac{4}{2}{t}^2$

$t^2=4t$

$t=4$ or $0$

Option $-$ B is correct.

with respect to the ground,

the distance covered by second

body is = d.

Applying $2^{nd}$ $e{q}^n$ of motion,

$d=\left(0\right)t+\frac{4\left(t^2\right)}{2}$ [initial vel. of it is zero]

$d=2t^2=2(4{)}^2=16\times 2=32m$

Option $-$ d is correct.