Question

The distance covered in the $n^{th}$ second is proportional to

• A. $n^2$
• B. $n$
• C. $2n-1$
• D. $2n^2-1$

Answer 1

The correct option is C $2n-1$

$u=0m/s,a=-g$

$S_{n^{th}}=u+\frac{a}{2}[2n-1]$

$S_{n^{th}}=0-\frac{g}{2}[2n-1]$

$S_n\propto 2n-1$