Question

The distance from a point (1, 3) to the line 4x + 3y + 12 = 0 is

• A. 4 units
• B. 5 units
• C. 6 units
• D. 7 units
• E. none of these

Answer 1

Answer: (B)

5 units

The distance of point $(x_0,y_0)$ from a line $ax+by+c=0$ is

$r=\frac{|a{x}_o+b{y}_o+c|}{\sqrt{a^2+b^2}}$

$\therefore$ distance of point $(1,3)$ from the line $4x+3y+12=0$ is

$r=\frac{|4\times 1+3\times 3+12|}{\sqrt{4^2+3^2}}$

$=>r=\frac{|25|}{\sqrt{25}}$

$=>r=5$units