The distance (in feet) jumped by an athlete in a long jump competition are given as :
6.45 , 7.01 , 6.78 , 6.82 , 6.64 , 6.5

What is the mean distance he jumped?

6.9

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6.6

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6.7

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6.8

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Solution

The correct option is C
6.7

Mean = $\frac{S u m o f o b s e r v a t i o n s}{N o . o f O b s e r v a t i o n s}$

= $\frac{6.45 + 7.01 + 6.78 + 6.82 + 6.64 + 6.5}{6}$

= $\frac{40.2}{6}$

= 6.7 feet

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