The distance (in units) between the points (1, 3), (5, 6) is _____.
Using the distance formula
d = √(x2−x1)2+(y2−y1)2 (here x1 = 1, x2 = 5,y1 = 3,y2 = 6) we have, d = √(5−1)2+(6−3)2 = √(4)2+(3)2 = √25 = 5
The distance between the points (1,3) and (5,6) is ___units.