Question

The distance of a point $(2,3)$ from the $x-$ axis is

• A. 3 units
• B. 2 units
• C. 5 units
• D. 1 unit

Answer 1

Since, we have the distance between two points $A(x_1,y_1)$ and $B(x_2,y_2)$ is $=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$......(i)
Given points $A(x_1,y_1)=(2,3)$ and the other point lies on $x-$axis. so the other $B(x_2,y_2)=(2,0)$ as the the $y-$ordinate on $x-$ axis is equals to $0$ and also this point is closure of $A$ among other points on $x-$axis.
Substitute the values of given points in equation(i), we get required distance as
$=\sqrt{({2-2)}^2+(0-3{)}^2}$
$=\sqrt{0^2+(-3{)}^2}$
$=\sqrt{(3{)}^2}$
$=3$units
Therefore, the distance between two given points is$=3$ units

Alternatively, the distance of a point from $x-$ axis is the length of its $y-$coordinate,
In this case, the y-ordinate is $3$.
Hence, the required distance is $=3$units

Therefore, the correct option is A ( $3$ units)