The distance of a point $P (x, y)$ from the origin is....

\sqrt{x^{2} - y^{2}}

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\sqrt{x^{2} + y^{2}}

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\sqrt{x^{3} - y^{3}}

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\sqrt{x^{3} + y^{3}}

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Solution

The correct option is B $\sqrt{x^{2} + y^{2}}$
$\begin{matrix} D i s t a n c e = \sqrt{{(x - 0)}^{2} + {(y - 0)}^{2}} = \sqrt{x^{2} + y^{2}} \end{matrix}$

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Similar questions

(x_{1}, y_{1}), (x_{2}, y_{2}), (x_{3}, y_{3})

\frac{y_{2} - y_{3}}{x_{2} x_{3}} + \frac{y_{3} - y_{1}}{x_{3} x_{1}} + \frac{y_{1} - y_{2}}{x_{1} x_{2}} = 0

Find the centroid of the triangle with vertices A $(x_{1}, y_{1})$ , B $(x_{2}, y_{2})$ and C $(x_{3}, y_{3})$ .

\frac{x^{2} + y^{2}}{x^{2} - y^{2}} = \frac{17}{8}

\frac{x^{3} + y^{3}}{x^{3} - y^{3}}

[\frac{x^{3} + y^{3}}{{(x - y)}^{2} + 3 x y}] \div [\frac{{(x + y)}^{2} - 3 x y}{x^{3} - y^{3}}] \times \frac{x y}{x^{2} - y^{2}}

[\frac{x^{3} + y^{3}}{(x - y)^{2} + 3 x y}] + [\frac{(x + y)^{2} - 3 x y}{x^{3} - y^{3}}] \times \frac{x y}{x^{2} - y^{2}}

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