The distance of a point $P (x, y, z)$ from its image in xy-plane is

2 | y |

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2 | z |

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2 | x |

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2 \sqrt{x^{2} + y^{2} + z^{2}}

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Solution

The correct option is A $2 | y |$
Distance of a point $(x, y, z)$ from $x y$ -plane is given by $| z |$ .
Therefore,
The distance of the point $(x, y, z)$ from its image in $x y$ -plane $= 2 | z |$

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