Question

The distance of planet Jupiter from the Sun is $5.2$ times that of the earth. Find the period of revolution of Jupiter around the Sun.

Answer 1

We know that $T^2\propto r^3$

$\therefore \frac{T_J^2}{T_E^2}=\frac{r_J^3}{r_E^3}\Rightarrow T_J^2=\frac{T_E^2.{\left(5.2r_E\right)}^3}{r_E^3}=140.6T_E^2\Rightarrow T_J=11.86T_E$

where $T_E$ is the time period of eath.