The distance of separation between the 3rd and 2nd orbit in the hydrogen atom is-A- 1-058 - 10-8 cmB- 0-529 - 10-8 cmC- 2-116 - 10-8 cmD- 2-645 - 10-8 cm

The correct option is D r_2 = 0.529 × 10^ 8× 2^2 r_3 = 0.529 × 10^ 8× 3^2 r_3 r_2 =0.529 × 10^ 8 (9 4) =2.645 × 10^ 8 ...

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Relation between Linear and Angular Speed

The distance ...

Question

The distance of separation between the $3^{r d}$ and $2^{n d}$ orbit in the hydrogen atom is:

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Solution

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h = 6.624 \times 10^{- 27} e r g - s e c

m = 9.108 \times 10^{- 28} g

r = 0.529 \times 10^{- 8} c m

b

24 {mL mol}^{- 1}

Van der waals constant "b" of helium is $24 m L m o l^{- 1}$ . Find molecular diameter of helium.

Ψ_{1 s} = [\frac{1}{\sqrt{π a_{o}^{3}}}] e^{- r / a_{0}}

r =

a_{0} = 0.529 \times 10^{- 8} c m

1 s

r =

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