The distance of the centres of moon and earth is D. The mass of earth is 81 times the mass of the moon.
At what distance from the centre of the earth, the gravitational force will be zero

$\frac{D}{2}$

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$\frac{2 D}{3}$

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$\frac{4 D}{3}$

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$\frac{9 D}{10}$

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Solution

The correct option is D
$\frac{9 D}{10}$

Force will be zero at the point of zero intensity
$x = \frac{{\sqrt{m}}_{1}}{{\sqrt{m}}_{1} + {\sqrt{m}}_{2}} d = \frac{\sqrt{81 M}}{\sqrt{81 M} + \sqrt{M}} D = \frac{9}{10} D$

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The distance of the centres of moon and earth is D. The mass of earth is 81 times the mass of the moon. At what distance from the centre of the earth, the gravitational force will be zero

The correct option is D 9D10 Force will be zero at the point of zero intensity x=√m1√m1+√m2d=√81M√81M+√MD=910D

The distance of the centres of moon and earth is D. The mass of earth is 81 times the mass of the moon.
At what distance from the centre of the earth, the gravitational force will be zero

The correct option is D
$\frac{9 D}{10}$

Force will be zero at the point of zero intensity
$x = \frac{{\sqrt{m}}_{1}}{{\sqrt{m}}_{1} + {\sqrt{m}}_{2}} d = \frac{\sqrt{81 M}}{\sqrt{81 M} + \sqrt{M}} D = \frac{9}{10} D$