Family of Planes Passing through the Intersection of Two Planes
The distance ...
Question
The distance of the point (−1,−5,−10) from the point of intersection of the line x−22=y+14=z−212 and the plane x−y+z=5 is
A
2√11
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B
√126
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C
13
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D
14
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Solution
The correct option is C13 Let x−22=y+14=z−212=k Then, x=2k+2 y=4k−1 z=12k+2 Substitute in the equation of plane x−y+z=5 10k+5=5 k=0 Point of intersection =(2,−1,2) Distance from (−1,−5,−10)=√32+42+122=13