The distance of the point (2,3) from the line 2x−3y+9=0 measured along a line x−y+1=0 is
Consider the following equation.
2x−3y+9=0
x−y+1=0
p=(2,3)
2x−2y=−2
2x−3y=−9
x=(6,7)
Using a distance formula. And calculate x $ y value we get.
d=√(x2−x$1)2+(y2−y1)2
=√(6−2)2+(7−3)2
=2√2
Hence, this is the required answer.