Question

The distance of the point $(-2,3)$ from the line $12x-5y-2=0$ $\frac{41}{k}$ then k=

Answer 1

As we know that

Distance of a point $(x_1,y_1)$ from the line $ax+by+c=0$ is $\frac{|a{x}_1+b{y}_1+c|}{\sqrt{a^2+b^2}}$

Distance of the point $(-2,3)$ from the line $12x-5y-2=0$ is $\frac{|12(-2)-5\left(3\right)-2|}{\sqrt{{12}^2+(-5{)}^2}}=\frac{|-24-15-2|}{13}=\frac{41}{13}$