The distance of the point (-2,5,4) from the Z-axis is units.
A
2√5
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B
√41
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C
5
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D
√29
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Solution
The correct option is D√29 We know that, the distance of a point P(x,y,z) from Z-axis is √x2+y2. Hence, the distance of the given point from the Z-axis is: √(−2)2+52=√29