Question

The distance of the point (–4, 7) from y-axis is _________.

Answer 1

The distance between the point (–4, 7) and y-axis can be determined by assuming a point (0, 7) on y-axis.

The distance between $\left(x_1,y_1\right)\mathrm{and}\left(x_2,y_2\right)\mathrm{is}\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$.

Therefore, the distance between (–4, 7) and (0, 7)$=\sqrt{{\left(0-\left(-4\right)\right)}^2+{\left(7-7\right)}^2}$
= $\sqrt{{\left(-4\right)}^2}$
​ = $\sqrt{16}$
​ = 4

Hence, the distance of the point (–4, 7) from y-axis is 4 units.