Question

The distance of the point P(−6, 8) from the origin is [CBSE 2013C]
(a) 8 (b) $2\sqrt{7}$ (c) 6 (d) 10

Answer 1

The distance of a point (x, y) from the origin O(0, 0) is $\sqrt{x^2+y^2}$.
Let P(x = −6, y = 8) be the given point. Then
$$\begin{gathered} OP=\sqrt{x^2+y^2} \\ =\sqrt{{\left(-6\right)}^2+8^2} \\ =\sqrt{36+64} \\ =\sqrt{100}=10 \end{gathered}$$
Hence, the correct answer is option (d).