The distance, s metres, which a falling body covers in time t seconds, is 4.8 times the square of the time t. Rewrite the above information as an equation in s and t.

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Solution

$s = 4.8 t^{2}$

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The distance, s metres, which a falling body covers in time t seconds, is 4.8 times the square of the time t. Rewrite the above information as an equation in s and t.

s=4.8t2

$s = 4.8 t^{2}$