The distance traveled by an object along a straight line in time t is given by s=3−4t+5t2, the initial velocity of the object is:
A
3 unit
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B
-3 unit
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C
4 unit
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D
-4 unit
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Solution
The correct option is D -4 unit Given distance travelled by an object along a straight line in time is 3−4t+5t2 Here, the velocity dsdt=−4+10t Hence, initial veocity will be ∣∣∣u=dsdt∣∣∣t=0=−4 unit.