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Byju's Answer
Standard XII
Chemistry
Longest Chain Rule
The distance ...
Question
The distance travelled by a body in the nth second is given by Sn= u+a/2(2n-1) where u is initial velocity and a is acceleration. The dimensional formula of Sn is
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Similar questions
Q.
Check the correctness of the relation
S
n
t
h
=
u
+
a
2
(
2
n
−
1
)
, where
u
is initial velocity,
a
is acceleration and
S
n
t
h
is the distance travelled by the body in
n
t
h
second.
Q.
The equation which is dimensionally consistent in the following is:
(Where
S
n
=
distance traveled by a body in
n
t
h
second,
u
=
initial velocity,
a
=
acceleration,
T
=
time period,
r
=
radius of the orbit,
M
=
Mass of the sun,
G
=
universal gravitational constant,
C
=
RMS velocity,
P
=
pressure and
d
=
density.)
Q.
A body moving with uniform acceleration travels a distance
s
n
= (0.4n + 9.8) m in
n
t
h
second. Initial velocity of the body is (in
m
s
−
1
)
Q.
If the distance travelled by a body in the nth second is given by (4+6n) m then find the initial velocity and acceleration of the body.
Q.
A body is moving in a straight line with initial velocity
u
and uniform acceleration
a
. Sum of the distances travelled in
n
th
and
(
n
+
1
)
th
seconds
is
50
m
. If
v
is its velocity after
n
seconds
and
u
=
5
m/s
, then
v
u
is
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