CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Longest Chain Rule

The distance ...

Question

The distance travelled by a body in the nth second is given by Sn= u+a/2(2n-1) where u is initial velocity and a is acceleration. The dimensional formula of Sn is

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. Check the correctness of the relation

S_{n t h} = u + \frac{a}{2} (2 n - 1)

u

is initial velocity,

a

is acceleration and

S_{n t h}

is the distance travelled by the body in

n t h

Q. The equation which is dimensionally consistent in the following is:

S_{n} =

distance traveled by a body in

n^{t h}

u

=

initial velocity,

a

=

T

=

r

=

radius of the orbit,

M

=

Mass of the sun,

G

=

universal gravitational constant,

C

=

P

=

d

=

Q. A body moving with uniform acceleration travels a distance

s_{n}

= (0.4n + 9.8) m in

n^{t h}

second. Initial velocity of the body is (in

m s^{- 1}

)

Q. If the distance travelled by a body in the nth second is given by (4+6n) m then find the initial velocity and acceleration of the body.

Q. A body is moving in a straight line with initial velocity

u

and uniform acceleration

a

. Sum of the distances travelled in

n^{th}

(n + 1)^{th} seconds

50 m

v

is its velocity after

n seconds

u = 5 m/s

\frac{v}{u}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Nomenclature of Saturated Hydrocarbons

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Longest Chain Rule

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon