Question

The distance travelled by a body starting with a velocity of $20{ms}^{-1}$, and moving with an acceleration of $2{ms}^{-2}$, in the $8^{th}$ second is ____ m.

• A. 35
• B. 20
• C. 120
• D. 10

Answer 1

The correct option is A 35

Initial velocity $u=20m/s$
Acceleration $a=2m/s^2$
Distance covered in $8^{th}$ second $S_t=u+\frac{a}{2}(2t-1)$
where $t=8s$
Thus, $S_8=20+\frac{2}{2}(2\times 8-1)=35m$