You visited us 1 times! Enjoying our articles? Unlock Full Access!

Net Acceleration for Non Uniform Circular Motion

The distance ...

Question

The distance x covered by a particle in one-dimensional motion varies with time t as $x^{2} = a t^{2} + 2 b t + c$ . The acceleration of the particle varies as:

x^{- 3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{3 / 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{- 2 / 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x^{- 3}$
Here the answer A: $x^{- 3}$

Suggest Corrections

Similar questions

x

t

x^{2} = a t^{2} + 2 b t + c .

x

x^{- n}

n

n

x

t

x^{2} = a t^{2} + 2 b t + c

x

x^{- n}

n

n

x

x^{2} = 2 t^{2} + 6 t + 1.

x

x

x = a t^{2} - b t^{3}

T

x

x = a t^{2} - b t^{3}

Join BYJU'S Learning Program