MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Horizontal and Vertical Components of Projectile Motion

The distance ...

Question

The distance (x) covered by a particle moving on a straight line path at any instant is given by t=ax^2+bx. If the instantaneous velocity of the particle be v. What is the acceleration of the particle? 1)2av^3 2)-2av^3 3)2av^2 4)-2av^2

Open in App

Solution

Suggest Corrections

thumbs-up

4

Similar questions

Q. The position of a particle moving on a straight line path is given by

x = 12 + 18 t + 9 t^{2} m

t

s

. Its acceleration at any instant is

Q. At any instant, the velocity and acceleration of a particle moving along a straight line v and a. The speed of the particle is increasing if

Q. A particle moves along a straight line. Its position at any instant is given by

x = 32 t - \frac{8 t^{3}}{3}

x

m

t

s

. The acceleration of the particle at the instant when particle is at rest will be

Q. Velocity of particle moving along a straight line at any time

t

v = cos (\frac{π}{3} t)

. The distance travelled by the particle in the first two seconds is equal to

Q. The displacement of a particle moving along

x

axis is given by

X = (4 t^{2} + 3 t + 7) μ

. Calculate instantaneous velocity and instantaneous acceleration at

t = 2 S

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Falling Balls in Disguise

PHYSICS

Watch in App

explore_more_icon

Explore more

Horizontal and Vertical Components of Projectile Motion

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon