The distances covered by a particle thrown in a vertical plane, in horizontal and vertical directions at any instant of time t are x=3t and y=4tâ4t2. The range of the particle is
A
3m
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B
4m
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C
2.4m
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D
5m
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Solution
The correct option is A3m Range, x=3t height, y=4t−4t2 for time of flight T, y=0⇒4t−4t2=0⇒t=1 Range,x=3t⇒x=3m