The distances of Neptune and Saturn from the Sun are respectively 1013 and 1012 meters and their periodic times are respectively Tn and TS. If their orbits are assumed to be circular, the value of TnTS is :
A
100
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B
10√10
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C
110√10
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D
10
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Solution
The correct option is A10√10 Time period T2=4π2GMR3 i.e T2∝R3 ⇒(TnTS)2=(RnRS)3 Given: RnRS=10131012=10 (TnTS)2=103 ⇒TnTS=103/2=10√10