The distances traversed during equal interval of time by a freely falling body from rest are in ratio
A
1:3:5:7..................
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1:4:9:16................
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1:2:3:4..................
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1:1:1:1..................
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A1:3:5:7.................. Answer (3)
Distance travelled in the nth second Sn=u+a2(2n−1)
If u=0⇒Sn=a2(2n−1)
Hence, S1:S2:S3:S4:⋯=1:3:5:7