The distribution of height of 50 children are given. If the mean height for the distribution is 117.8 cm, then complete the following table.
Height110115x1120121125Number of students6814f143
x1=118,f1=15
xififixi11066601158920x11414x1120f1120f112144841253375Total∑fi=35+f1∑f1x1=2439+14x1+120f1
Now, ∑fi=50
⇒35+f1=50⇒f1=15
We know that, ¯x=∑x1fi∑fi
⇒117.8=2439+14x1+120f150⇒5890=2439+14x1+120×15[∵f1=15]⇒5890−4239=14x1⇒1651=14x1∴x1=117.93≈118