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Byju's Answer
Standard XII
Mathematics
Collinear Vectors
The divergenc...
Question
The divergence of vector
→
r
=
x
^
i
+
y
^
j
+
z
^
k
is
A
^
i
+
^
j
+
^
k
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B
3
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C
0
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D
1
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Solution
The correct option is
B
3
→
r
=
x
^
i
+
y
^
j
+
z
^
k
Divergence is
▽
.
→
r
=
(
∂
∂
x
^
i
+
∂
∂
y
^
j
+
∂
∂
z
^
k
)
.
(
x
^
i
+
y
^
j
+
z
^
k
)
=
1
+
1
+
1
=
3
Suggest Corrections
9
Similar questions
Q.
If
r
=
x
^
i
+
y
^
j
+
z
^
k
find
(
→
r
×
^
i
)
(
→
r
×
^
j
)
+
x
y
Q.
For a position vector
→
r
=
x
^
i
+
y
^
j
+
z
^
k
the norm of the vector can be defined as
|
→
r
|
=
√
x
2
+
y
2
+
z
2
.
Given a function
ϕ
=
l
n
|
→
r
|
,
its gradient
▽
ϕ
is
Q.
If vectors
→
a
1
=
x
^
i
−
^
j
+
^
k
and
→
a
2
=
^
i
+
y
^
j
+
2
^
k
are collinear, then a possible unit vector parallel to the vector
x
^
i
+
y
^
j
+
z
^
k
is :
Q.
The vectors
¯
a
=
x
^
i
−
2
^
j
+
5
^
k
and
¯
b
=
^
i
+
y
^
j
−
z
^
k
are collinear if
Q.
The position vector of a point P is
→
r
=
x
^
i
→
+
y
^
j
+
z
^
k
,
where
x
ϵ
N
,
y
ϵ
N
,
z
ϵ
N
,
and
→
a
=
→
i
+
→
j
+
→
k
→
. If
→
r
.
→
a
=
10
, the number of possible positions of P is
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