Question

The divisor when the quotient, dividend and the remainder are respectively $547,171282$ and $71$ is equal to

• A. $333$
• B. $323$
• C. $313$
• D. $303$

Answer 1

Answer: (C)

$313$

We know that,

$Dividend=(Divisor\times Quotient)+Remainder$

Let $x$ be the required divisor then
$x\times 547+71=171282$
or $x\times 547=171282-71=171211$
$\therefore x=\frac{171211}{547}=313$