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Question

The domain and range for sinh1x is

A
R - {0}
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B
R- {1}
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C
R
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D
None of these
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Solution

The correct option is A R
sinhx=exex2
sinhx is satisfying for all values of x
Hence xR
Now, sinhx=e2x12ex
Let, ex=t
t212t=sinhx=y
t21=2ty
t22ty1=0
t>0
4y2+4>0
y2+1>0
which is true for all value.
Hence yR

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