$T h e d o m a i n o f d e f i n i t i o n o f t h e f u n c t i o n, f (x) g i v e n b y t h e e q u a t i o n 2^{x} + 2^{y} = 2 i s$

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Solution

The correct option is D

$I t i s g i v e n t h a t 2^{x} + 2^{y} = 2 \forall x, y ϵ R t h e r e f o r e, 2^{x} = 2 - 2^{y} < 2 \Rightarrow 0 < 2^{x} < 2 T a k i n g l o g f o r b o t h s i d e w i t h b a s e 2. \Rightarrow l o g_{2} 0 < l o g_{2} 2^{x} < l o g_{2} 2 H e n c e d o m a i n i s - \infty$

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2^{x} + 2^{y} = 2

2^{x} + 2^{y} = 2

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2^{x} + 2^{y} = 2

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