Question

The domain of $f\left(x\right)=\frac{\sqrt{x-1}}{\sqrt{x-1}}$ is

• A. $R$
• B. $R-\left\{1\right\}$
• C. $x>1$
• D. none of these

Answer 1

The correct option is C $x>1$

$f\left(x\right)=\frac{\sqrt{x-1}}{\sqrt{x-1}}$
For the square root to be defined,
$x-1>0\Rightarrow x>1$