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Question

The domain of f(x)=112sinx is

A
(,)
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B
R{nπ+(1)nπ6;nZ}
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C
R{nπ:nZ}
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D
R{nπ+(1)nπ3;nz}
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Solution

The correct option is A R{nπ+(1)nπ6;nZ}
f is defined if denominator is not equal to zero
12sinx0
sinx12
xnπ+π6,nZ
f is defined for R{nπ+π6nz}

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