Question

The domain of $f\left(x\right)={\left(\frac{2x+1}{x^2-10x-11}\right)}^{2020}$ is

• A. $(0,\infty )$
• B. $(-1,11)$
• C. $R-\{-1,11\}$
• D. $R-[-1,11]$

Answer 1

The correct option is C $R-\{-1,11\}$

$f\left(x\right)={\left(\frac{2x+1}{x^2-10x-11}\right)}^{2020}$

For $f\left(x\right)$ to be defined,
$x^2-10x-11\ne 0\Rightarrow (x-11)(x+1)\ne 0\Rightarrow x\ne -1,11$