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Question

The domain of f(x)=log5(x2+4x+1) is

A
(,23)
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B
(2+3,)
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C
(23,2+3)
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D
(,23)(2+3,)
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Solution

The correct option is D (,23)(2+3,)
For f(x)=log5(x2+4x+1) to be defined, we get
x2+4x+1>0x2+4x+43>0(x+2)2>3x+2>3, x+2<3x(,23)(2+3,)

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